3b^2-26b=-48

Solution for 3b^2-26b=-48 equation:

3b^2-26b=-48

We move all terms to the left:

3b^2-26b-(-48)=0

We add all the numbers together, and all the variables

3b^2-26b+48=0

a = 3; b = -26; c = +48;
Δ = b2-4ac
Δ = -262-4·3·48
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-10}{2*3}=\frac{16}{6}
=2+2/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+10}{2*3}=\frac{36}{6}
=6
$